|(assuming the feedback was moved exponentially down from 100% to 50% during the first run of the loop)|
|(assuming the feedback was moved briskly down from 100% to 50% during the first run of the loop. Thanks to Andy Butler for this graphic and for making the point.)|
|loop duration||LD||s (seconds)||[0,...||real|
|process duration||PD||s (seconds)||[0,...||real|
|repetitions (number of)||R||[0,...||integer|
|(1)||V = V0 * (F/100)R||Resulting volume V at the end of repetition R for a loop with a feedback setting of F|
|(2)||R = PD / LD||Number of repetitions depending on process duration and loop duration|
What volume factor x will a 10-second-loop have decreased to after 60 seconds with a feedback setting of 80% ?
What feedback setting F will lead to a decrease in Volume by 90% within 30 seconds for a 10 second loop?
V = V0 * ( 100 - 90 ) / 100; (decrease by 90%)
V0 * 0.1 = V0 * (F/100)(PD/LD); (using formula (1))
How many repetions R does it take until a loop's volume will have decreased to 10% with a feedback setting of 90% ?
V = V0 * 0.1;
V0 * 0.1 = V0 * (F/100)R; (using formula (1))
0.1 = (9/10)R;
log (0.1) = R * log (0.9);
R = log(0.1) / log (0.9) = 22;
© Bernhard Wagner, 2006.